Loading src/compiler/float-tran.lisp +23 −19 Original line number Diff line number Diff line Loading @@ -2031,29 +2031,33 @@ (labels ((calc-exp (x) (when x (nth-value 1 (decode-float x)))) (min-exp () ;; Use decode-float on the least positive float of the ;; appropriate type to find the min exponent. If we don't ;; know the actual number format, use double, which has the ;; widest range (including double-double-float). (calc-exp (if (eq 'single-float (numeric-type-format arg)) (bound-func #'(lambda (arg) (nth-value 1 (decode-float arg))) x))) (min-exp (interval) ;; (decode-float 0d0) returns an exponent of -1022. But ;; (decode-float least-positive-double-float returns -1073. ;; Hence, if the low value is less than this, we need to ;; return the exponent of the least positive number. (let ((least (if (eq 'single-float (numeric-type-format arg)) least-positive-single-float least-positive-double-float))) (max-exp () (if (or (interval-contains-p 0 interval) (interval-contains-p least interval)) (calc-exp least) (calc-exp (bound-value (interval-low interval)))))) (max-exp (interval) ;; Use decode-float on the most postive number of the ;; appropriate type to find the max exponent. If we don't ;; know the actual number format, use double, which has the ;; widest range (including double-double-float). (or (calc-exp (bound-value (interval-high interval))) (calc-exp (if (eq 'single-float (numeric-type-format arg)) most-positive-single-float most-positive-double-float)))) (let* ((interval (interval-func #'calc-exp (interval-abs (numeric-type->interval arg)))) (lo (or (interval-low interval) (min-exp))) (hi (or (interval-high interval) (max-exp)))) most-positive-double-float))))) (let* ((interval (interval-abs (numeric-type->interval arg))) (lo (min-exp interval)) (hi (max-exp interval))) (specifier-type `(integer ,(or lo '*) ,(or hi '*)))))) (defun decode-float-sign-derive-type-aux (arg) Loading Loading
src/compiler/float-tran.lisp +23 −19 Original line number Diff line number Diff line Loading @@ -2031,29 +2031,33 @@ (labels ((calc-exp (x) (when x (nth-value 1 (decode-float x)))) (min-exp () ;; Use decode-float on the least positive float of the ;; appropriate type to find the min exponent. If we don't ;; know the actual number format, use double, which has the ;; widest range (including double-double-float). (calc-exp (if (eq 'single-float (numeric-type-format arg)) (bound-func #'(lambda (arg) (nth-value 1 (decode-float arg))) x))) (min-exp (interval) ;; (decode-float 0d0) returns an exponent of -1022. But ;; (decode-float least-positive-double-float returns -1073. ;; Hence, if the low value is less than this, we need to ;; return the exponent of the least positive number. (let ((least (if (eq 'single-float (numeric-type-format arg)) least-positive-single-float least-positive-double-float))) (max-exp () (if (or (interval-contains-p 0 interval) (interval-contains-p least interval)) (calc-exp least) (calc-exp (bound-value (interval-low interval)))))) (max-exp (interval) ;; Use decode-float on the most postive number of the ;; appropriate type to find the max exponent. If we don't ;; know the actual number format, use double, which has the ;; widest range (including double-double-float). (or (calc-exp (bound-value (interval-high interval))) (calc-exp (if (eq 'single-float (numeric-type-format arg)) most-positive-single-float most-positive-double-float)))) (let* ((interval (interval-func #'calc-exp (interval-abs (numeric-type->interval arg)))) (lo (or (interval-low interval) (min-exp))) (hi (or (interval-high interval) (max-exp)))) most-positive-double-float))))) (let* ((interval (interval-abs (numeric-type->interval arg))) (lo (min-exp interval)) (hi (max-exp interval))) (specifier-type `(integer ,(or lo '*) ,(or hi '*)))))) (defun decode-float-sign-derive-type-aux (arg) Loading